To check if the square root of a number is an integer in Python, you can use the `math.sqrt()`

function from the `math`

module and check if the square root value is equal to its integer representation. Here’s an example:

```
import math
number = 16
square_root = math.sqrt(number)
is_integer = square_root == int(square_root)
if is_integer:
print("The square root is an integer")
else:
print("The square root is not an integer")
```

In this example, we import the `math`

module to access the `sqrt()`

function. We define a variable `number`

with the value `16`

, but you can replace it with any other number you want to check.

We calculate the square root of `number`

using `math.sqrt(number)`

and store it in the `square_root`

variable. Then, we check if the `square_root`

is equal to its integer representation, obtained by converting it to an integer using `int(square_root)`

.

If the square root is an integer, the condition `square_root == int(square_root)`

evaluates to `True`

, and we print “The square root is an integer”. Otherwise, if the square root is not an integer, we print “The square root is not an integer”.

Keep in mind that the `math.sqrt()`

function returns a floating-point number, so we need to check if it is equal to its integer representation to determine if the square root is an integer.

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