# How to Compare Sets Using the isdisjoint() Function in Python?

To compare sets using the `isdisjoint()` function in Python, you can use it to check if two sets have no common elements. The `isdisjoint()` function returns `True` if the sets have no intersection (i.e., no common elements), and `False` otherwise. Here’s an example:

``````set1 = {1, 2, 3, 4, 5}
set2 = {6, 7, 8}

if set2.isdisjoint(set1):
print("set2 and set1 have no common elements")
else:
print("set2 and set1 have at least one common element")``````

In this example, we have two sets, `set1` and `set2`. We use the `isdisjoint()` function on `set2` and pass `set1` as the argument. The function checks if there are any common elements between the two sets. If there are no common elements, the code will print “set2 and set1 have no common elements”. Otherwise, it will print “set2 and set1 have at least one common element”.

The output of the above code will be:

``set2 and set1 have no common elements``

By using the `isdisjoint()` function, you can easily compare sets in Python to check if they have any common elements.