To find missing numbers in a sequence in JavaScript, you can first sort the array and then iterate through it, comparing each value to the expected value. If a value is missing, you can add it to a separate array.

Here’s an example of finding missing numbers in an array of integers:

```
function findMissingNumbers(array) {
array.sort((a, b) => a - b);
let missingNumbers = [];
for (let i = array[0]; i < array[array.length - 1]; i++) {
if (array.indexOf(i) === -1) {
missingNumbers.push(i);
}
}
return missingNumbers;
}
const array = [3, 7, 1, 2, 8, 4, 5];
console.log(findMissingNumbers(array)); // [6]
```

In this example, we first sort the input array in ascending order. Then, we iterate from the first element to the second to last element in the array and use the `Array.indexOf()`

method to check if the current number is in the array. If it’s not, we add it to the `missingNumbers`

array. Finally, we return the `missingNumbers`

array, which contains the missing numbers in the sequence.

## + There are no comments

Add yours