To find both the largest and smallest numbers in an array using JavaScript, you can use the `Math.max()`

and `Math.min()`

methods and spread operator `...`

:

```
var numbers = [1, 2, 3, 4, 5];
var largest = Math.max(...numbers);
var smallest = Math.min(...numbers);
console.log(largest); // Output: 5
console.log(smallest); // Output: 1
```

In this example, `Math.max()`

and `Math.min()`

are called with the spread operator `...`

to spread the elements of the `numbers`

array into separate arguments. The result of the `Math.max()`

call is the largest number in the `numbers`

array, and the result of the `Math.min()`

call is the smallest number in the `numbers`

array.

Alternatively, you can loop through the array and keep track of both the largest and smallest numbers so far:

```
var numbers = [1, 2, 3, 4, 5];
var largest = Number.NEGATIVE_INFINITY;
var smallest = Number.POSITIVE_INFINITY;
for (var i = 0; i < numbers.length; i++) {
if (numbers[i] > largest) {
largest = numbers[i];
}
if (numbers[i] < smallest) {
smallest = numbers[i];
}
}
console.log(largest); // Output: 5
console.log(smallest); // Output: 1
```

In this example, `largest`

and `smallest`

are variables that keep track of the largest and smallest numbers found so far. The `for`

loop iterates through each element in the `numbers`

array, and the `if`

statements check whether the current element is greater than the largest number found so far and whether the current element is smaller than the smallest number found so far, and update `largest`

and `smallest`

respectively if either is true.

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