How to Pass **kwargs Arguments to Another Function in Python?

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To pass **kwargs arguments to another function in Python, you can simply pass them as arguments to the function with the ** operator. Here’s an example:

def foo(**kwargs):
    bar(**kwargs)

def bar(**kwargs):
    print(kwargs)

foo(a=1, b=2, c=3)

In this example, the foo function takes in **kwargs as a parameter and calls the bar function with **kwargs as an argument. The bar function then prints out the kwargs dictionary.

When you run the code, you’ll see the following output:

{'a': 1, 'b': 2, 'c': 3}

This shows that the bar function successfully received the kwargs dictionary that was passed to it from the foo function.

Note that you can also pass regular arguments along with **kwargs using the normal argument syntax. For example:

def foo(a, b, **kwargs):
    bar(a, **kwargs)

def bar(a, **kwargs):
    print(a)
    print(kwargs)

foo(1, 2, b=3, c=4)

This would output:

1
{'b': 3, 'c': 4}

In this example, the foo function takes in two regular arguments, a and b, along with **kwargs. It then calls the bar function with a as a regular argument and **kwargs as a keyword argument. The bar function then prints out a and kwargs.

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