# How to Solve Codeforces 570B in Python?

Codeforces problem 570B, also known as “Simple Game”, asks us to find the optimal position for a player to start, given the number of cells and the position of the dangerous cell.

Here’s how to solve this problem in Python:

``````# Get the number of cells and the position of the dangerous cell
n, m = map(int, input().split())

# Calculate the optimal position for the player to start
if n == 1:
position = 1
elif m <= n // 2:
position = m + 1
else:
position = m - 1

# Print the optimal position for the player to start
print(position)``````

In this solution, we first get the number of cells and the position of the dangerous cell using `map(int, input().split())`.

We then calculate the optimal position for the player to start using an `if` statement. If there is only one cell, the player should start in that cell. If the dangerous cell is closer to the beginning of the cells than to the end, the player should start in the cell to the right of the dangerous cell. Otherwise, the player should start in the cell to the left of the dangerous cell.

Finally, we print the optimal position for the player to start using `print(position)`.

Note: This solution assumes that the dangerous cell is not at the beginning or end of the cells. If the dangerous cell is at the beginning or end, you’ll need to modify the code to account for this.