Codeforces problem 677A, also known as “Vanya and Fence”, asks us to calculate the minimum width of a fence needed to prevent a person of height h from passing, given the heights of n friends and the width of the fence.

Here’s how to solve this problem in Python:

```
# Get the number of friends and the height of the fence
n, h = map(int, input().split())
# Get the heights of the friends
heights = list(map(int, input().split()))
# Initialize the width of the fence
width = n
# Loop over the heights of the friends
for height in heights:
# If the friend is taller than the fence, increase the width by 1
if height > h:
width += 1
# Print the minimum width of the fence
print(width)
```

In this solution, we first get the number of friends and the height of the fence using `map(int, input().split())`

. We then get the heights of the friends using `list(map(int, input().split()))`

.

We initialize the width of the fence to `n`

, since each friend can walk through the fence without any issues.

We then loop over the heights of the friends using a `for`

loop. For each friend, if their height is greater than the height of the fence, we increase the width of the fence by 1 using `width += 1`

.

Finally, we print the minimum width of the fence using `print(width)`

.

Note: This solution assumes that the width of the fence is not a factor in preventing the person from passing. If the width of the fence is a factor, you’ll need to modify the code to account for this.

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