The PermCheck problem on Codility is a task that asks you to determine whether a given array is a permutation or not. Here is an example of how to solve this problem in Python using Codility:

```
def solution(A):
n = len(A)
count = [0] * n
for num in A:
if num > n:
return 0
if count[num-1] == 1:
return 0
count[num-1] = 1
return 1 if sum(count) == n else 0
```

In this solution, we first create a list `count`

of length `n`

filled with zeroes, where `n`

is the length of the input array `A`

. We then iterate through `A`

and check if each element is greater than `n`

or if we have seen that element before. If either of these conditions is true, we return 0, indicating that the array is not a permutation.

If we have not seen the element before and it is a valid value, we set the corresponding element in `count`

to 1. After iterating through `A`

, we check if the sum of the values in `count`

is equal to `n`

. If it is, we return 1, indicating that the array is a permutation. If it is not, we return 0.

To use this function, simply call `solution(A)`

with the appropriate input array `A`

. The function will return 1 if `A`

is a permutation and 0 if it is not.

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