How to Sort Files by Content in Python?

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To sort files by content in Python, you can follow these steps:

  1. Use the glob module to obtain a list of filenames in the directory you want to sort.
  2. Create a list to hold the contents of each file.
  3. Use a for loop to iterate over the list of filenames.
  4. Use the open function to open each file for reading.
  5. Use the read method to read the contents of each file into a string variable.
  6. Append the string variable to the list created in step 2.
  7. Use the sorted function to sort the list of file contents.
  8. Iterate over the sorted list of file contents and process each file as desired.

Here’s an example implementation:

import glob

# Obtain a list of filenames in the directory
filenames = glob.glob("path/to/directory/*.txt")

# Create a list to hold the contents of each file
contents = []

# Iterate over the list of filenames
for filename in filenames:
    # Open the file for reading
    with open(filename, "r") as file:
        # Read the contents of the file into a string variable
        file_contents = file.read()
        # Append the string variable to the list of contents
        contents.append(file_contents)

# Sort the list of contents
sorted_contents = sorted(contents)

# Process each file in the sorted list
for content in sorted_contents:
    # Do something with the file
    print(content)

In this example, we assume that the files are plain text files. If the files contain binary data, you will need to use a different method to read the contents of each file. You may also want to add error handling to the code in case a file cannot be opened or read.

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